Saturday, 1 August 2020

Two Sum - Hashing Problem

Problem : Find two elements in an array whose sum is x.
Following is the implementation:


Longest Consequent Sub-sequence - Hashing Problem

To find longest consequent sub-sequence in an array, following is the implementation using hashmap:



Maximum Distance Between Two Occurences Of Same Element - Hashing Problem

To find the maximum distance between two occurrences of same element, we can store the elements in hashmap and compare max index distance. Following is the implementation:



Check If Two Arrays Are Equal - Hashing Problems

To check if two arrays are equals, lengths and elements along with their frequency need to be considered. For this, a hashmap can be used. Following is the implementation:



Thursday, 30 July 2020

Linear Probing - Coursera Algorithms

Linear probing is used to resolve collisions in hashing. It takes less space and has better cache performance.

An array of size M > number of elements N is used such that:

1. Hash - map key to i between 0 and M-1.
2. Insert - at table index i, if not free - try i+1, i+2 etc
3. Search - search table index i, if occupied and no match - try i+1, i+2 etc

Following is the implementation :

Separate Chaining - Coursera Algorithms

To deal with collisions in hashing, separate chaining implementation can be used, where M linked lists(<number of elements N) are used such that :

1. Hash - map key to i between 0 and M-1.
2. Insert - at the front of ith chain.
3. Search - in ith chain.

Easier to implement and clustering less sensitive to poorly designed hash function.

Following is the implementation:


Hash Functions - Coursera Algorithms

We can do better than the sequential/binary search or search through BST/red-black BST, by storing the data in key-indexed table. Hash functions compute the array index from key. We need to handle the hash implementation, equality test and collision resolution when two keys hash to the same index.

There are several hashing implementations, some of them being :
1. 31*initial_hash_value+ current element value or current object hashcode.
2. Modular - Math.abs(key.hashCode() & 0x7fffffff)%M returning a hash between 0 and M-1

Following code experiments with what happens when we override equals/hashcode: